Details about my Ken smith burner bass

[Ken Smith]

Originally Posted by nathan bossoh

Ah, I was asking you, but ok I can send an email to you if needed instead,

Thanks

We are good. That is what I would have replied back with. On the other hand, I only email from my office. I can do forum responses from home though in the evenings and weekends so this place works fine.

[nathan bossoh]

Originally Posted by Ken Smith

We are good. That is what I would have replied back with. On the other hand, I only email from my office. I can do forum responses from home though in the evenings and weekends so this place works fine.

Ok, if its alright here then i will await your response in the evening, i just kind of want to know any information you could give me on it as iv'e had it for a while but don't really know too much about it. I only know what the first 6 numbers of the serial number mean.

Thanks

[Ken Smith]

Originally Posted by nathan bossoh

Ok, if its alright here then i will await your response in the evening, i just kind of want to know any information you could give me on it as iv'e had it for a while but don't really know too much about it. I only know what the first 6 numbers of the serial number mean.

Thanks

I did answer you in my first post.

On the number, 94 1196 sw5..

94=1994,

1196 = number of Burners made to date.

[nathan bossoh]

Oh cool ok. I though there was more you were gonna add to it but that is fine Ken.

Thank you for the info!

[Ken Smith]

Originally Posted by nathan bossoh

Oh cool ok. I though there was more you were gonna add to it but that is fine Ken.

Thank you for the info!

Did you read the info in my first reply? Everything is there and with a link to read the specs.

[Lawrence Foulquier]

Hi Nathan,

I own this bass now!
Did you sanded it, or was it a previous owner?

[JonPaulsen]

Just about to get an old Burner, most likely a standard since it's a solid color. I just wanted to ask if the specs are the same for the BSRB and the Burners when it comes to body woods?
So, Standard = alder?

Thanks,
Jon-Inge